Answer
$m= 6.75 kg$
Work Step by Step
We have $Q = mL_{fusion}$
But according to given condition $Q= 1.0kg× L_{vaporization}$
$ \therefore mL_{fusion} = 1.0kg× L_{vaporization}$
$\implies m = \frac{1.0kg×L_{vaporization}}{L_{fusion}}$
$\implies m = \frac{1.0kg× 22.6 ×10^5J/kg }{ 33.5 × 10^4J/kg }$
$\implies m= 6.75kg$
