Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 205: 39d

Answer

$$x=5.7 \mathrm{m}$$

Work Step by Step

At $x=7.0 \mathrm{m},$ the potential energy is $U_{3}=45 \mathrm{J}$ , which exceeds the initial total energy $E_{1} .$ Thus, the particle can never reach there. At the turning point, the kinetic energy equal zero. Between $x=5$ and 6 $\mathrm{m}$ , the potential energy is given by $$ U(x)=15+30(x-5), \quad 5 \leq x \leq 6 $$ Thus, the turning point is found by solving $$37=15+30(x-5),$$ which yields $$x=5.7 \mathrm{m}$$
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