Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 205: 38b

Answer

$v = 12.6m/s$

Work Step by Step

Finding the kinetic energy at $U(J) = 0$: $E_0=E_A$ $K_0 + U_0 = K_A + U_A$ $K_0 = K_A + U_A - U_0$ $K_0 = 12J + 4J - 0J$ $K_0 = 16J$ Using $K_0$ to find the speed at $x=6.5m$ $K_0 = \frac{mv^2}{2}$ $2K_0 = {mv^2}$ $\frac{2K_0}{m} = {v^2}$ $v =\sqrt \frac{2K_0}{m} $ $v =\sqrt \frac{2 \times 16J}{0.2kg} $ $v = 12.6m/s$
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