Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 175: 68

Answer

1.5 kJ

Work Step by Step

According to the work-energy theorem, $K_{f}-K_{i}=W$ $K_{i}=\frac{1}{2}mv_{i}^{2}=\frac{1}{2}m\times0^{2}=0$ Therefore, we can write $K_{f}-0=W$ $= Fd\cos\theta=200\,N\times8.0\,m\times\cos 20^{\circ}$ $=1500\,J$
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