Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 6 - Force and Motion-II - Problems - Page 144: 54c

Answer

$\frac{dF}{dT} = -\frac{8\pi^2~m~r}{T^3}$

Work Step by Step

We can find an expression for $v$ in terms of the period $T$: $T = \frac{2\pi~r}{v}$ $v = \frac{2\pi~r}{T}$ We can find $\frac{dF}{dT}$: $F = \frac{mv^2}{r}$ $F = \frac{m~(\frac{2\pi~r}{T})^2}{r}$ $F = \frac{4\pi^2~m~r}{T^2}$ $\frac{dF}{dT} = -\frac{8\pi^2~m~r}{T^3}$
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