Answer
$=806\ {m}.$
Work Step by Step
We use the discussion of part (a).
The horizontal component of velocity remains unchanged, so,
using the result of part (a), $ v_{0}=202m/s$, along with $\theta=-37^{o}$
the horizontal distance traveled is
$v_{x}t=(v_{0}\cos\theta_{0})t$
$=(202\mathrm{m}/\mathrm{s})\cos(-37.0^{\mathrm{o}})(5.00\mathrm{s})$
$=806\mathrm{m}.$
