Answer
$N=1.36\times 10^4$
Work Step by Step
We know that:
$dsin{\theta}=m\lambda$
The above formula can be written as:
$d=\frac{m\lambda}{sin{\theta}}$
We plug in the known values to obtain:
$d=\frac{2(600\times 10^{-9})}{sin(33.0)}=2.2033\mu m$
Now, we find $N$ as:
$N=\frac{0.03}{2.2033\times 10^{-6}}=1.36\times 10^4$
