Answer
$N=4.84\times 10^3$
Work Step by Step
We know that:
$N=\frac{\lambda_{avg}}{m\Delta \lambda}$
We plug in the known values to obtain:
$N=\frac{590.2nm}{2(0.061nm)}=4.84\times 10^3$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 36 - Diffraction - Problems - Page 1114: 76
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