Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 34 - Images - Problems - Page 1041: 75d

Answer

$i=-3.3cm$

Work Step by Step

Shrunken, upright images can only be formed by diverging lenses. Therefore, the lens is diverging and the focal length is negative (f=-10cm). To find the image distance, use the formula $$\frac{1}{f}=\frac{1}{p}+\frac{1}{i}$$ Solving for $i$ yields $$\frac{p}{pf}-\frac{f}{pf}=\frac{1}{i}$$ $$\frac{p-f}{pf}=\frac{1}{i}$$ $$i=\frac{pf}{p-f}$$ Substituting values of $f=-10cm$ and $p=+5.0cm$ yields $$i=\frac{(5.0cm)(-10cm)}{5.0cm+10cm}=-3.3cm$$
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