## Fundamentals of Physics Extended (10th Edition)

$i=-3.3cm$
Shrunken, upright images can only be formed by diverging lenses. Therefore, the lens is diverging and the focal length is negative (f=-10cm). To find the image distance, use the formula $$\frac{1}{f}=\frac{1}{p}+\frac{1}{i}$$ Solving for $i$ yields $$\frac{p}{pf}-\frac{f}{pf}=\frac{1}{i}$$ $$\frac{p-f}{pf}=\frac{1}{i}$$ $$i=\frac{pf}{p-f}$$ Substituting values of $f=-10cm$ and $p=+5.0cm$ yields $$i=\frac{(5.0cm)(-10cm)}{5.0cm+10cm}=-3.3cm$$