Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 34 - Images - Problems - Page 1041: 69d

Answer

$i=-10cm$

Work Step by Step

Using the lens equation $$\frac{1}{f}=\frac{1}{p}+\frac{1}{i}$$ solve for $i$. $$\frac{1}{f}-\frac{1}{p}=\frac{1}{i}$$ $$\frac{p}{pf}-\frac{f}{pf}=\frac{1}{i}$$ $$\frac{p-f}{pf}=\frac{1}{i}$$ $$i=\frac{pf}{p-f}$$ Substituting known values of $p=+5.0cm$ and $f=+10cm$ yields an image distance of $$i=\frac{(10cm)(5.0cm)}{5.0cm-10cm}=-10cm$$
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