Answer
$\theta_B = 58.0^{\circ}$
Work Step by Step
In part (a), we found that $n_2 = 1.60$
We can find the Brewster angle $\theta_B$:
$\theta_B = tan^{-1}~\frac{n_2}{n_1}$
$\theta_B = tan^{-1}~\frac{1.60}{1.00}$
$\theta_B = 58.0^{\circ}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 33 - Electromagnetic Waves - Problems - Page 1009: 107b
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