Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 33 - Electromagnetic Waves - Problems - Page 1008: 89b

Answer

The lower limit of the Brewster angle is $~~55.5^{\circ}$

Work Step by Step

On the graph in Figure 33-18, we can see that the index of refraction in quartz for light with a wavelength of $700~nm$ is $n = 1.456$ We can find the Brewster angle: $\theta_B = tan^{-1}~\frac{n_2}{n_1}$ $\theta_B = tan^{-1}~\frac{1.456}{1.00}$ $\theta_B = 55.5^{\circ}$ The lower limit of the Brewster angle is $~~55.5^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.