Answer
Since the whole spectrum of colors is refracted, the refracted light is white.
Work Step by Step
We can use Snell's law to find $\theta_r$, the angle of refraction of red light:
$n_2~sin~\theta_r = n_1~sin~\theta_1$
$sin~\theta_r = \frac{n_1~sin~\theta_1}{n_2}$
$\theta_r = sin^{-1}~(\frac{n_1~sin~\theta_1}{n_2})$
$\theta_r = sin^{-1}~(\frac{1.456~sin~42.00^{\circ}}{1.00})$
$\theta_r = 77.0^{\circ}$
We can use Snell's law to find $\theta_b$, the angle of refraction of blue light:
$n_2~sin~\theta_b = n_1~sin~\theta_1$
$sin~\theta_b = \frac{n_1~sin~\theta_1}{n_2}$
$\theta_b = sin^{-1}~(\frac{n_1~sin~\theta_1}{n_2})$
$\theta_b = sin^{-1}~(\frac{1.470~sin~42.00^{\circ}}{1.00})$
$\theta_b = 79.6^{\circ}$
Since the whole spectrum of colors is refracted, the refracted light is white.
