Answer
$E=5.3 \times 10^{11} \mathrm{~N} / \mathrm{C} .$
Work Step by Step
Using Formula,
$$
E=\frac{e}{4 \pi \varepsilon_0 r^2}\\=\frac{\left[1.60 \times 10^{-19} \mathrm{C} \mid\left[8.99 \times 10^9 \mathrm{~N} \cdot \mathrm{m}^2 / \mathrm{C}^2\right\rceil\right.}{\left[5.2 \times\left. 10^{-11} \mathrm{~m}\right|^2\right.}\\=5.3 \times 10^{11} \mathrm{~N} / \mathrm{C} .
$$
