Answer
The magnetic of the magnetic flux is $9.2 \mathrm{mWb}$.
Work Step by Step
From formula, we have
$$
\left(\Phi_B\right)_{\text {in }}=\left(\Phi_B\right)_{\text {out }}=0.0070 \mathrm{~Wb}+(0.40 \mathrm{~T})\left(\pi r^2\right)\\=9.2 \times 10^{-3} \mathrm{~Wb} .
$$
Thus, the magnetic of the magnetic flux is $9.2 \mathrm{mWb}$.
