Answer
These particles will move out of the page:
2, 5, 6, 9, 10
Work Step by Step
Let $q$ be the charge on the particle.
We can write an equation for the magnitude of the force due to the electric field:
$F_E = q~E$
We can write an equation for the magnitude of the force due to the magnetic field:
$F_B = q~v~B$
When $v = \frac{E}{B},$ then the magnitudes of these two forces are equal.
If $v \lt \frac{E}{B}$, then the magnitude of $F_B$ increases while $F_E$ stays the same.
In this case, $F_E$ dominates.
If $v \gt \frac{E}{B}$, then the magnitude of $F_B$ increases while $F_E$ stays the same.
In this case, $F_B$ dominates.
Particle 2:
$F_B$ is directed out of the page
$F_E$ is directed into the page
Since the speed is "Greater", then $F_B$ dominates.
Particle 2 will move out of the page.
Particle 5:
$F_B$ is directed out of the page
$F_E$ is directed out of the page
Particle 5 will move out of the page.
Particle 6:
$F_B$ is directed out of the page
$F_E$ is directed out of the page
Particle 6 will move out of the page.
Particle 9:
$F_B = 0$
$F_E$ is directed out of the page
Particle 9 will move out of the page.
Particle 10:
$F_B = 0$
$F_E$ is directed out of the page
Particle 10 will move out of the page.
