Answer
The equivalent resistance between points A and B is 4.0Ω.
Work Step by Step
We can redraw the circuit as in the diagram below.
Here the 3.0 Ω resistor is parallel to the 6.0 Ω resistor. Its equivalent resistance is $(6.0 Ω×3.0 Ω)/(6.0Ω+3.0Ω)=2.0Ω$ and is connected to a 10.0 Ω resistor. This (10.0 Ω + 2.0 Ω) resistance is connected parallel to (4.0 Ω + 2.0 Ω).
Hence, the equivalent resistance between points A and B is $(12.0Ω×6.0Ω)/(12.0Ω+6.0Ω)=4.0 Ω$
