Answer
$V_2=4V$
Work Step by Step
We know that
$V_2=IR_2$
$\implies V_2=\frac{{\epsilon}R_2}{R_1+R_2+R_3}$
We plug in the know values to obtain:
$V_2=\frac{12(4)}{3+4+5}$
$V_2=4V$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 27 - Circuits - Problems - Page 801: 81
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