Answer
$4.46$
Work Step by Step
First, we have to find out the number of kwh for 31 days
$(100w)(\frac{1kw}{10^3w})(31days)(24\frac{hr}{day})=74.4 kwh$
Thus, we obtain:
$=(74.4kwh)(\frac{\$0.06}{kwh})=4.46$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 26 - Current and Resistance - Problems - Page 768: 49a
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