Answer
$E = 1.69\times 10^{-2}~V/m$
Work Step by Step
We can find the magnitude of the electric field:
$E = \frac{V}{L}$
$E = \frac{i~R}{L}$
$E = \frac{i~\rho~L}{A~L}$
$E = \frac{i~\rho}{A}$
$E = \frac{(2.00~A)(1.69\times 10^{-8}~\Omega\cdot m)}{2.00\times 10^{-6}~m^2}$
$E = 1.69\times 10^{-2}~V/m$
