Answer
$v=0.32\frac{Km}{s}$
Work Step by Step
We know that:
$U=\frac{1}{4\pi \epsilon_{\circ}}\frac{2e^2}{r}$
We plug in the known values to obtain:
$U=\frac{8.99\times 10^9\times 2\times (1.6\times 10^{-19})^2}{0.01}=4.6\times 10^{-26}J$
Thus, the initial kinetic energy is
$\frac{1}{2}m_ev^2=4.6\times 10^{-26}$
This can be rearranged and simplified as:
$v=\sqrt{\frac{2\times4.6\times 10^{-26}}{m}}$
$v=\sqrt{\frac{2\times4.6\times 10^{-26}}{9.11\times 10^{-31}}}=3.2\times 10^2=0.32\frac{Km}{s}$
