Answer
$16.3 \mu C$
Work Step by Step
Dipole moment, $P= 1.47 D= 1.47\times3.34\times10^{-30}Cm$
Distance, $r= 52.0\times10^{-9}m$.
Potential due to a dipole at a point which is on the axis of the dipole at a distance r is given by
V= $\frac{1}{4\pi\epsilon_{0}}\frac{P}{r^{2}}$
$= 8.987\times10^{9}Nm^{2}/C^{2}\times\frac{1.47\times3.34\times10^{-30}Cm}{(52.0\times10^{-9}m)^{2}}$ $=1.63\times10^{-5}J/C= 16.3 \mu C$