Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 24 - Electric Potential - Problems - Page 711: 24



Work Step by Step

We know that: $V=\frac{KQ}{R}$ We plug in the known values to obtain: $V=\frac{9\times 10^9(-25.6\times 10^{-12})}{3.71\times 10^{-2}}$ $V=-6.21V$
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