Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 23 - Gauss' Law - Questions - Page 677: 3

Answer

All three Gaussian surfaces have the same magnitude of the electric field at any point on the surface.

Work Step by Step

We can use Equation (23-15) to find an expression for the electric field at each Gaussian surface. radius $R$: $E = \frac{1}{4\pi~\epsilon_0}~\frac{Q}{R^2}$ radius $2R$: $E = \frac{1}{4\pi~\epsilon_0}~\frac{4Q}{(2R)^2} = \frac{1}{4\pi~\epsilon_0}~\frac{Q}{R^2}$ radius $3R$: $E = \frac{1}{4\pi~\epsilon_0}~\frac{9Q}{(3R)^2} = \frac{1}{4\pi~\epsilon_0}~\frac{Q}{R^2}$ When we can rank the Gaussian surfaces according to the magnitude of the electric field at any point on the surface, all three Gaussian surfaces have the same magnitude of the electric field at any point on the surface.
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