Answer
The electric field is the same at any point on the three Gaussian surfaces.
Work Step by Step
According to Gauss' law:
$\Phi = \frac{q_{enc}}{\epsilon_0}$
Also, for each of these three cylinders with the same surface area $A$:
$\Phi = E~A$
Then, for each of these three Gaussian surfaces:
$E~A = \frac{q_{enc}}{\epsilon_0}$
$E = \frac{Q}{A~\epsilon_0}$
The electric field is the same at any point on the three Gaussian surfaces.
