Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 23 - Gauss' Law - Problems - Page 683: 61a

Answer

$E = 0$

Work Step by Step

We can draw a Gaussian sphere with radius $r$ with the same common center as the two spherical shells. We can find the electric field at a distance $r$ from the common center: $\epsilon_0~\Phi = q_{enc}$ $(\epsilon_0)~(E)(4\pi~r^2) = q_{enc}$ $E = \frac{q_{enc}}{4\pi~\epsilon_0~r^2}$ $E = \frac{0}{4\pi~\epsilon_0~r^2}$ $E = 0$
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