Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 23 - Gauss' Law - Problems - Page 682: 42

Answer

$Q=4.9\times 10^{-10}C$

Work Step by Step

We know that: $E=\frac{\sigma}{\epsilon_{\circ}}$ This can be rearranged as: $\sigma=\epsilon_{\circ}E$ We plug in the known values to obtain: $\sigma=8.85\times 10^{-12}(55)=4.9\times 10^{-10}\frac{C}{m^2}$ We also know that: $\sigma=\frac{Q}{A}$ This can be rearranged as: $Q=\sigma A$ We plug in the known values to obtain: $Q=4.9\times 10^{-10}(1.0)=4.9\times 10^{-10}C$
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