Answer
$8.2\times 10^{10}$
Work Step by Step
We can find the excess electrons per cubic meter as:
$\frac{\frac{q}{e}}{V}=\frac{\frac{2.0\times 10^{-7}}{1.6\times 10^{-19}}}{15}=8.2\times 10^{10}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 23 - Gauss' Law - Problems - Page 679: 8b
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