Answer
$\phi=-0.015\frac{Nm^2}{C}$
Work Step by Step
We know that:
$\phi=EAcos{\theta}$
We plug in the known values to obtain:
$\phi=1800(3.2\times 10^{-3})^2cos(180^{\circ}-35^{\circ})=-0.015\frac{Nm^2}{C}$
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