Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 23 - Gauss' Law - Problems - Page 679: 1

Answer

$\phi=-0.015\frac{Nm^2}{C}$

Work Step by Step

We know that: $\phi=EAcos{\theta}$ We plug in the known values to obtain: $\phi=1800(3.2\times 10^{-3})^2cos(180^{\circ}-35^{\circ})=-0.015\frac{Nm^2}{C}$
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