Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 22 - Electric Fields - Problems - Page 658: 83a

Answer

$U=-1.49*10^{-26}J$

Work Step by Step

We are given the vectors $\vec{P}$ and $\vec{E}$, so we can use the equation $U=-\vec{P}\cdot\vec{E}$ $\vec{P}=(3.00\hat{i}+4.00\hat{j})(1.24*10^{-30}C*m)$ and $\vec{E}=4000 \frac{N}{C}$ So, taking the dot product, we get the answer: $U=-\vec{P}\cdot\vec{E}=-(3.00*4000\frac{N}{C}+4.00*0\frac{N}{C})(1.24*10^{-30}C*m)$ $U=-3.00*4000*1.24*10^{-30}J=-1.49*10^{-26}J$ $U=-1.49*10^{-26}J$
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