Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 21 - Coulomb's Law - Problems - Page 625: 3

Answer

$r=1.39 m$

Work Step by Step

According to coulomb's law $F=\frac{q_1q_2}{4\pi{\epsilon_{\circ}}r^2}$ or $r=\sqrt{\frac{q_1q_2}{4\pi{\epsilon_{\circ}}F}}$ putting the values, we get $r=\sqrt{\frac{26\times10^{-6}\times47\times10^{-6}}{4(3.14)(8.854\times10^{-12})(5.70)}}$ $r=1.39 m$
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