Answer
$x\approx.222m$
Work Step by Step
Like in the previous problem, we first solve for time:
$t=\sqrt {\frac{2x}{g}}=\sqrt \frac{2(2.00m)}{(9.8m/s^{2})}=.639s$
The second droplet has been falling for one third of the time: $t_{3}=\frac{(.639s)}{3}=.213s$
We now solve for distance:
$x=\frac{1}{2}(9.8m/s^{2})(.213s)^{2}\approx.222m$
