## Fundamentals of Physics Extended (10th Edition)

$x=19.6m$
The package travels upwards for two seconds with an initial velocity of $19.6m/s$ upwards. The maximum height above the break-free point can be calculated with the equation $v_{f}^{2}=v_{0}^{2}+2gx$. The final velocity at the maximum height is $0$, so the final velocity term reduces to $0$. Solving the equation for x, we get $x=\frac{-v_{0}^{2}}{2g}=\frac{-(19.6m/s)^{2}}{2(-9.8m/s^{2})}=19.6m$