Answer
The graphs are as follow :
Work Step by Step
We have given that pipe wrench was dropped.
Thus, the magnitude of initial velocity $u$ is zero.
That is, $u=0$ $m/s$.
Also, the final speed is $24$ $m/s$.
Thus, the magnitude of final velocity $v$ is $24$ $m/s$.
That is, $v=24$ $m/s$.
Here $a$ is equal to the acceleration due to gravity $g$.
Thus, $a=9.81$ $m/s^2$
Substituting $v=24m/s$, $u=0$ $m/s$ and $a=9.81$ $m/s^2$ in equation $v=u+at$.
We get, $24=0+9.81t\implies t=\dfrac{24}{9.81} s\implies t=2.44648$ $s$.
Thus, graphs will be made from time $t=0$ $s$ to $t=2.44648$ $s$.
Using equation $y=ut+\dfrac{1}{2}at^2$.
We get, equation $y=\dfrac{9.81}{2}t^2$.
Thus, y versus t graph is a parabola.
Using equation $v=u+at$.
We get, equation $v=9.81t$.
Thus, v versus t graph is a straight line with end points $(0,0)$ and $(2.44648,24)$.
Also, we have $a=9.81$.
Thus, a versus t graph is a horizontal line segment from $(0,9.81)$ and $(2.44648,29.35779)$.
Thus, we get the following graphs :
