Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Problems - Page 577: 3b

Answer

$T= 220$ C$^{\circ}$

Work Step by Step

We know that the ideal gas equation is: $PV=nRT$ We first rearrange this equation to make $T$ the subject of the formula: $T=\frac{PV}{nR}$ We then put the values in this formula to find $T$, $T=\frac{1.06\times10^5(1500\times10^{-6}m^3)}{0.038(8.31)}$ $T=493$ K $T=493-273=220$ C$^{\circ}$
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