Answer
$m=0.933kg$
Work Step by Step
We know that;
$n=7.50\times 10^{24}(\frac{1}{6.022\times 10^{23}})=12.5mol$
We also know that
$m=M\times n$
We plug in the known values to obtain:
$m=74.9\times 12.5=0.933Kg$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 19 - The Kinetic Theory of Gases - Problems - Page 577: 1
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