Answer
$$57.6^{\circ} \mathrm{C} $$
Work Step by Step
$\begin{aligned} T_{2} &=T_{c}+\frac{T_{H}-T_{c}}{1+k_{b}\left(k_{c}+k_{a}\right) / k_{c} k_{a}} \\ \\ &=0.00^{\circ} \mathrm{C}+\frac{100^{\circ} \mathrm{C}-0.00^{\circ} \mathrm{C}}{1+109(235+401) /[(235)(401)]} \\ \\ &=57.6^{\circ} \mathrm{C} \end{aligned}$
