Answer
$\Delta V=0.432cm^3$
Work Step by Step
We know that;
$\Delta V=V\beta \Delta T$
As $\beta=3\alpha$,
$\Delta V=3\alpha V\Delta T$
We plug in the known values to obtain:
$\Delta V=125\times 3(23\times 10^{-6})(50)=0.432cm^3$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 18 - Temperature, Heat, and the First Law of Thermodynamics - Problems - Page 546: 73
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
