Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 18 - Temperature, Heat, and the First Law of Thermodynamics - Problems - Page 546: 79

Answer

$\frac{70}{3}$ $J$

Work Step by Step

Work done is $\int p dV$. Plugging in the given, we get $\int 10V^2dV$ from $V = 1$ to $V = 2$. The result is $10\frac{2^3-1^3}{3}$ = $\frac{70}{3}$ $J$
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