Answer
$f=1031$ Hz
Work Step by Step
To find the apparent frequency of the sound, use the Doppler effect equation, which is $$f'=f(\frac{v \pm v_o}{v \mp v_s})$$ Since the source is moving towards the observer, the apparent tone must be higher than the actual tone. Substituting values into the equation using $v=330m/s$ yields $$f'=(1000Hz)(\frac{330m/s}{330m/s-10m/s})=1031Hz$$
