Answer
The pressure amplitude is $~~0.892~Pa$
Work Step by Step
In part (b), we found that $s_m = 171~nm$
We can find the pressure amplitude $p_m$:
$p_m = s_m~v~\rho~\omega$
$p_m = s_m~v~\rho~2\pi~f$
$p_m = (171\times 10^{-9}~m)~(343~m/s)(1.21~kg/m^3)~(2\pi)(2000~Hz)$
$p_m = 0.892~Pa$
The pressure amplitude is $~~0.892~Pa$
