Answer
Option (a) is not correct
Work Step by Step
The displacement $x(t)$ of SHM given by equation 15-3 in the form
\begin{equation}
x=x_{m} \cos (\omega t+\phi)
\end{equation}
The acceleration $a$ is the second derivation of the above equation
\begin{equation*}
a=-\omega^{2} x_{m} \cos (\omega t+\phi) = - \omega x
\end{equation*}
The acceleration is directly proportional to $x$ and negative, so option (a) is wrong
