Answer
Greater.
Work Step by Step
Potential energy for a mass-spring system is defined as $U=\frac{1}{2}kx^2$. So, the maximum potential energy can be defined as $U=\frac{1}{2}kA^2$. The amplitude in the second experiment is greater than the first experiment. As $A$ increases, $A^2$ increases for all $A>0$. Therefore, the maximum potential energy must be greater for the second experiment.
