Answer
$\alpha = \frac{2F}{mL}$
Work Step by Step
We can find the angular acceleration about the center of mass due to the force $F$:
$\tau = I \alpha$
$\frac{L}{6} F = (\frac{1}{12}mL^2) \alpha$
$\alpha = \frac{2F}{mL}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 15 - Oscillations - Problems - Page 443: 113b
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