Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 443: 111d

Answer

$t=4.4s$

Work Step by Step

The time period is given as: $T=\frac{2\pi}{\omega}$ $T=\frac{2\times 3.1416}{10}=0.628s$ It is given that there are 7 cycles. Therefore; $t=7T=7(0.628)=4.4s$
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