Answer
Net Force on window $=2.9\times10^{4}$ $N$
Work Step by Step
The pressure difference is equal to the net pressure in the window.
So, Net pressure on window $=1.0$ $atm$ $-0.96$ $atm$ $=0.04$ $atm$
Or,
Net pressure on window $=0.04\times10^{5}=4\times10^{3}$ $Pa$ [as $1$ $atm\approx 10^{5}Pa$]
Area of the window $=2.1m\times3.4m=7.14$ $m^{2}$
We know that:
$Pressure=\frac{Force}{Area}$
Or,
$Force=Pressure \times Area $
Substituting the known values and solving the equation gives:
$Force =(4\times10^{3})\times7.14 =2.8560\times10^{4}$ $N$
$Force\approx2.9\times10^{4}$ $N$
