Answer
Pressure increase $=1.1\times10^{5}$ $Pa$
Work Step by Step
The pressure increase is equal to the external pressure applied on the fluid.
And we have,
$Pressure=\frac{Force}{Area}$
Area of syringe’s circular piston $=\pi r^{2}$
$=3.14\times (1.1)^{2}=3.8$ $cm^{2} =3.8\times10^{-4}$ $m^{2}$
Substituting the known values and solving the above equation gives:
$Pressure=\frac{42}{3.8\times10^{-4}}$
$Pressure=1.1\times10^{5}$ $Pa$
