Answer
$a_g=7.6\frac{m}{s^2}$
Work Step by Step
We know that
$a_g=\frac{GM}{R^2}$
We plug in the known values to obtain:
$a_g=\frac{6.67\times 10^{-11}\times 4.1\times 10^{24}}{(6\times 10^6)^2}$
$a_g=7.6\frac{m}{s^2}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 13 - Gravitation - Problems - Page 380: 23a
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