Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 13 - Gravitation - Problems - Page 380: 17a

Answer

${W_{moon}}=17 N$

Work Step by Step

We can find the weight of an object on the moon surface using the equation: $\frac{W_{moon}}{W_{earth}}=\frac{g^\prime}{g}$...eq(1) where $W_{moon}$ is the weight of the object on the moon ,$W_{earth}$ is the weight of the object on the earth and $g^\prime$ and $g$ are acceleration due to gravity on moon and earth respectively. We know that $g^\prime=1.67\frac{m}{s^2}$ and $g=9.8\frac{m}{s^2}$. Putting values in eq(1) and solving: $\frac{W_{moon}}{100}=\frac{1.67}{9.8}$ ${W_{moon}}=100\times\frac{1.67}{9.8}$ ${W_{moon}}=17 N$
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