Answer
The x component of $F_3$ is $~~-24.4~N$
Work Step by Step
We can find the x component of $F_3$:
$\sum F_x = 0$
$F_{3x}+8.40~N+16.0~N = 0$
$F_{3x} = -8.40~N-16.0~N$
$F_{3x} = -24.4~N$
The x component of $F_3$ is $~~-24.4~N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 12 - Equilibrium and Elasticity - Problems - Page 353: 87a
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